[SMLets used on .Net Script]

Watch out for your versions, if you use the newer SDK binaries; you will have the DLL error, I have documented the solution here, including orchestrator natively using PowerShell v3+:

http://blogs.catapultsystems.com/mdowst/archive/2013/10/29/install-smlets-on-windows-server-2012-without-scsm-console/

[DHCP Windows 2008 R2 problem]

Hi again,

 

Thanks for replay. I am not sure that I dont need a DHCP relay agent. I can remember that MS has recommed me to do it.

Here is the message from Microsoft:

 

###################

Yes, we need to create 4 DHCP scopes, one for each subnet. To do so, we also need to configure DHCP relay agents for each subnet.

Generally speaking, there are two ways to configure DHCP relay agents .First, to configure routers act as a configure DHCP relay agents. In most cases, routers support DHCP relay. If your routers do not, contact your router manufacturer or supplier to find out if a software or firmware upgrade is available to support this feature.Second, we can configure a computer running Windows Server® 2008 to act as a relay agent by installing the DHCP Relay Agent service.

########################################

 

What do you mean about this resulotion?

 

Regards

 

Okay, if you want the range of 192.168.0.0 not to see 192.168.1.0 or 2.0 or 3.0 etc... as in four separate scopes/networks then you you need to create 4 scopes with the mask 255.255.255.0 for each (class C) and use a DHCP relay as these are segmented at layer 3, e.g. will need a router to communicate (layer 3). However, if you want these to be one address range with the mask 255.255.252.0 and therefore they all see each other with not router, only switches (layer 2) between the server and the clients then you do not need a DHCP relay agent and require only one scope.

 

I think it would help if you described your network infrastructure a little more, this would probably make your requirement clearer.

 

Kind Regards

[DHCP Windows 2008 R2 problem]

Yes, the ranges 192.168.0-3 are one network because of the mask, they have effectively been added together. You do not need a relay agent as they are not on different networks, unless you have some sort of router between. Please try as is, am sure you will see if will work fine. In my previous network, I actually used that exact subnet. So you are effectively creating a scope from 0.31 --> 3.200 making 254-30=224 on your 0 range, 254 on your 1 and 2 range and 199 on you 3rd. Therefore, 224+254+254+199=931 (remember to exclude the 0 & 255 addresses as these would have been typically used for network ID and broadcast on classfull).

 

Kind Regards

 

PS. Could you vote for me, to give me some good reputation.

[DHCP Windows 2008 R2 problem]

Hi Sabe75,

 

Thank you very much for your replay.Now I can understand you what you mean.Are you sure if I create a scope of 192.168.0.0/22 that particular IP-Range is included? I mean if I create a scope with for example:

 

192.168.0.30 until 192.168.3.200 /22, would I have 1022 hosts? Have I to create a DHCP Relay Agent too or not? I think yes

 

Kind Regards

 

Nick

Yes, the ranges 192.168.0-3 are one network because of the mask, they have effectively been added together. You do not need a relay agent as they are not on different networks, unless you have some sort of router between. Please try as is, am sure you will see if will work fine. In my previous network, I actually used that exact subnet. So you are effectively creating a scope from 0.31 --> 3.200 making 254-30=224 on your 0 range, 254 on your 1 and 2 range and 199 on you 3rd. Therefore, 224+254+254+199=931 (remember to exclude the 0 & 255 addresses as these would have been typically used for network ID and broadcast on classfull).

 

Kind Regards

[What Do All These Servers Do?]

Actually, DNS will give you pretty much everything; if your advertising a service it is being advertised from the DNS svr records....

 

It is more the network infrastructure which is a little more complex, e.g. switches and routers; but start from layer one and follow the cables; you'll find everything pretty soon

 

Kind Regards

[Local or AD Group Policy]

I have a user that runs a Windows Server 2008 R2 box that would like to have users be able to log into the machine with their AD account. Once they are logged in he would like them to be able to open Internet Explorer and view one certain Domain without Internet Explorer giving warnings and complaining at the users. This policy would be applied to Domain users on that box. I am wondering if that situation is possible and if so how or where to look for more info?

 

Please add more information, like what errors the person is seeing in IE; but yes you can configure via GPO.

[deploy W7 via mdt2010?]

Hi

 

yes, thanks.. I am way past this now.. I did som *shock* research ..! of course, I've hit multiple snags since, but that's all part of learning isn't it.

 

thank you for taking the time to respond!!

 

I would use SCCM rather than WDS. It does rely on WDS but you do not configure WDS just SCCM, it allows you to deploy multiple OS images and software as well, you can add in different drivers on a single image; the actual bonus is the extra features like software metering and remote tools.

 

There is also a free alternative to SCCM / WDS; although I have no experience in this. The link is: http://wpkg.org/WPKG_overview

 

Kind Regards

[DHCP Windows 2008 R2 problem]

Create one scope of 192.168.0.0/22, the 22 means subnet mask 255.255.252.0. Therefore a scope of 192.168.0.0 with that particular subnet mask includes:

 

192.168.0.0-192.168.0.255

192.168.1.0-192.168.1.255

192.168.2.0-192.168.2.255

192.168.3.0-192.168.3.255

 

The reason being that the 252 in the third octet converts to 11111100, the two 0's represent are the decimal figures of 2 & 1 going left to right and become part of the host section of the address, meaning you can have networks 0,1,2 & 3 (1+2) in the third octet (place of dots) as part of the same network, as normally a classfull 'C' class address would be 255 and therefore binary 11111111 (ones in the mask represents the network part of the address as opposed the host/computer). The technique is called supersubnetting, e.g. adding multiple networks together (as one).

 

Kind Regards

 

Here is an example of what you want I have excluded the first 9 addresses.

 

Kind Regards

[DHCP Windows 2008 R2 problem]

Create one scope of 192.168.0.0/22, the 22 means subnet mask 255.255.252.0. Therefore a scope of 192.168.0.0 with that particular subnet mask includes:

 

192.168.0.0-192.168.0.255

192.168.1.0-192.168.1.255

192.168.2.0-192.168.2.255

192.168.3.0-192.168.3.255

 

The reason being that the 252 in the third octet converts to 11111100, the two 0's represent are the decimal figures of 2 & 1 going left to right and become part of the host section of the address, meaning you can have networks 0,1,2 & 3 (1+2) in the third octet (place of dots) as part of the same network, as normally a classfull 'C' class address would be 255 and therefore binary 11111111 (ones in the mask represents the network part of the address as opposed the host/computer). The technique is called supersubnetting, e.g. adding multiple networks together (as one).

 

Kind Regards

[DHCP Windows 2008 R2 problem]

Just create a single scope of address range 192.168.0.0/22 mask 255.255.252.0 and create exclusions / reservations for your servers.

 

Kind Regards

 

Sabe75